8*3^2x=32

Solution for 8*3^2x=32 equation:

8*3^2x=32

We move all terms to the left:

8*3^2x-(32)=0

Wy multiply elements

24x^2-32=0

a = 24; b = 0; c = -32;
Δ = b2-4ac
Δ = 02-4·24·(-32)
Δ = 3072
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3072}=\sqrt{1024*3}=\sqrt{1024}*\sqrt{3}=32\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-32\sqrt{3}}{2*24}=\frac{0-32\sqrt{3}}{48}
=-\frac{32\sqrt{3}}{48}
=-\frac{2\sqrt{3}}{3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+32\sqrt{3}}{2*24}=\frac{0+32\sqrt{3}}{48}
=\frac{32\sqrt{3}}{48}
=\frac{2\sqrt{3}}{3}
$